I hope the attached picture is readable. 
If you support the hive at two points(left picture), then each point will take half the weight because of symmetry. There is no difference between the left and right support, so they will carry 1/2 of the weight. That does not change when one point is fixed on the ground and the other sits on a scale. It is  true if you lift the hive barely off the ground. 
If you lift it higher then it becomes more complicated: You have to consider the torque. the torque is defined as the force that tries to rotate a system( or bee box) times the radius (distance between the pivot point and the attack point of the  force. The sum of all torque components must be zero. 
right picture: imagine a slice of bee hive. its weight is the force (f) that wants to rotate the hive clockwise with an attack radius (r), so the slice creates a torque f*r. We have to sum up the torques of all slices, so the total torque is (with R being the length of the hive):
    t = integral from 0 to R of r*f dr 
(calculating f needs to include the rotation of the slice  relative to the bee box)
meanwhile the scale produces a torque T in the other direction: T= F*R
and we must have t=T for equilibrium.
So, long story short: If you lift the hive barely of the ground your scale should give you 1/2 of the weight
Did that help?

Jorg
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