In message <[log in to unmask]>, Automatic digest processor <[log in to unmask]> writes >... how many gallons of syrup do you get after >dissolving 112 pounds in 7 gallons of water? Is it just seven gallons? I >assume not, but if it is, how can you get that much sugar to dissolve? Using imperial measure: In the UK a winter mix is 2lbs sugar to 1pint water, therefore it is possible to mix up to 112lbs (7x16lbs) sugar with 7gallons (7x8pints) water. 1 gallon water weighs 10 lbs, therefore 7 gallons weigh 70 lbs, Assuming 112 lbs added to 70 lbs gives a total weight of 172lbs. I'm not sure what the s.g. of the syrup would be, but I guess about 1.5 which would give 11.5 galls (approx). My convertion from imperial to US is a bit rusty (after about 40+ years of non-use) but the ratio by weight of sugar to water (fl.oz.) =1.6:1 Therefore if 1 US gallon weighs 8lbs, the equivalent amount of sugar would be about 90lbs -I think they still have 16 ozs to the lb 'over there':-). >(Fortunate that we share the same language!) It certainly is!!! hth. -- Tom S