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Informed Discussion of Beekeeping Issues and Bee Biology

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Subject:
From:
Juanse Barros <[log in to unmask]>
Reply To:
Informed Discussion of Beekeeping Issues and Bee Biology <[log in to unmask]>
Date:
Sun, 27 May 2012 16:05:54 -0400
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Hi everyone, need your help.

I want to try a new "poison" on my bees to control nosemosis.

The poison (which I won't tell the name) leaflet says 40 ml per kg of live
animal (we are talking pigs in this case).

I know for each of my hives how many frames with bees.
http://apiaraucania.blogspot.com/2012/05/vendo-esporas-peso-cu.html

The question is how to guestimated the weight of each cluster proportional
to the frames with bees.

If a bee weight 100 mg and we have 30000 of them in a standard box with 10
frames, therefore we have 3 kg of live animal.

The volume of that box (rounding) will be 40x50x30 = 60000 cubic
centimetres, right?

therefore there are 0,00005 kg/cm3 on that big cluster.

Now, the volume of a sphere is 4/3 x Pi x r3 , therefore for that standard
box r= 24,2859 cm for 10 frames

or' 2,42859 PER FRAME ?

following the above suposition

  Frames w/Bees cm3 kg/animal  2 480 0,024  3 1620 0,081  4 3840 0,192  5
7500 0,375  6 12960 0,648  7 20580 1,029  8 30720 1,536  9 43740 2,187  10
60000 3,000

what I am doing wrong?

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