When considering the speed of revolution of an extractor, the relationship to
work with (and I shall write it out, as I don't know how to put symbols down
the line) is
 
force equals omega squared times radius
 
omega is the speed of rotation, so that if you double the speed force on the
honey in the comb is multiplied by 4; double the radius and the force is
merely doubled.
 
You have to juggle the speed and the radius.
 
Regards
 
Matthew J Allan